(2x+7)(5x^2-26x+5)=0

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Solution for (2x+7)(5x^2-26x+5)=0 equation: 


Simplifying
(2x + 7)(5x2 + -26x + 5) = 0

Reorder the terms:
(7 + 2x)(5x2 + -26x + 5) = 0

Reorder the terms:
(7 + 2x)(5 + -26x + 5x2) = 0

Multiply (7 + 2x) * (5 + -26x + 5x2)
(7(5 + -26x + 5x2) + 2x * (5 + -26x + 5x2)) = 0
((5 * 7 + -26x * 7 + 5x2 * 7) + 2x * (5 + -26x + 5x2)) = 0
((35 + -182x + 35x2) + 2x * (5 + -26x + 5x2)) = 0
(35 + -182x + 35x2 + (5 * 2x + -26x * 2x + 5x2 * 2x)) = 0
(35 + -182x + 35x2 + (10x + -52x2 + 10x3)) = 0

Reorder the terms:
(35 + -182x + 10x + 35x2 + -52x2 + 10x3) = 0

Combine like terms: -182x + 10x = -172x
(35 + -172x + 35x2 + -52x2 + 10x3) = 0

Combine like terms: 35x2 + -52x2 = -17x2
(35 + -172x + -17x2 + 10x3) = 0

Solving
35 + -172x + -17x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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